**The average score of a cricketer for 13 matches is 42 runs. If his average score for the first 5 matches is 54, then what was his average score (in runs) for last 8 matches?**- 37
- 39
- 34.5
- 33.5
- 37.5

Answer: Option C.

Total Score = Average * Number of matches

Total score of 13 matches = 13 × 42 = 546

Total score of first 5 matches = 5 × 54 = 270

Therefore, total score of last 8 matches = 546 – 270 = 276

Average = 276/8 = 34.5

Hence the answer is option C**Simple interest on a sum of money for 4 years at 7 p.c.p.a is Rs. 3584/-. What would be the compound interest (compounded annually) on the same amount of money for 2 years at 4p.c.p.a?**- Rs. 1,162.32
- Rs. 1,098.72
- Rs. 992.38
- Rs. 1,231.76
- Rs. 1,044.48

Answer: Option E.

Let P be the sum

Therefore,

3584 = (P * 7 * 4) / 100 => P = 12800/-

CI = 12800(1 + (4/100))2 - 12800

=> 13844.48 - 12800 = 1044.48/-

Hence the answer is option E

**6*136/8+132 / 628/16-26.25=?**- 15
- 24
- 18
- 12
- 28

Answer: Option C.

6*136/8+132 / 628/16-26.25

⇒ 234/13=18 Hence the answer is option C.**(1331)**^{1/3}/ 275 *5^{2}= ?- 2
- 4
- 1
- 2.5
- 3

Answer: Option C.

? = (1331)^{1/3}/275 *(5)^{2}

= (11^{3})^{1/3}/ 11*25 *(25)

=1 Hence the answer is option C.**(43)**^{2}+ 841 = (?)^{2}+ 1465- 41
- 35
- 38
- 33
- 30

Answer: Option B.

Using BODMAS

(?)^{2}= (43)^{2}+ 841 – 1465

= 1849 + 841 – 1465 = 1225

Therefore, ? = √1225 = 35

Hence the answer is option BZensar Preparation Links- Sample Aptitude Questions of Zensar
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**(216)**^{4}÷ (36)^{4}× (6)^{5}= (6)?- 13
- 11
- 7
- 9
- 10

Answer: Option D.

(6)^{?}= (216)^{4}÷ (36)^{4}× (6)5 =

216^{4}/36^{4}* 6^{5}=

6^{12}/ 6^{8}* 6^{5}=

6^{9}Therefore, ? = 9**(1097.63 + 2197.36 - 2607.24) ÷ 3.5 = ?**- 211.5
- 196.5
- 209.5
- 192.5
- 189.5

Answer: Option B.

? = (1097.63 + 2197.36 - 2607.24) ÷ 3.5 = 687.75 ÷ 3.5

= 196.5

Hence answer is option B**A certain number of capsules were purchased for Rs. 216/-. 15 more capsules could have been purchased in the same amount if each capsule was cheaper by Rs. 10/-. What was the number of capsules purchased?**- 6
- 14
- 8
- 12
- 9

Answer: Option D

Let x be the cost of each capsule and y be the no of capsules

Therefore, x = 216/y and x - 10 = 216/(y+15)

Putting the value of x from eq. 1 into eq. 2, we get

216/y - 216/(y+15) = 10

y^{2}+15y - 324 = 0

Solving for y, we get y = 12

Hence answer is option D.**What will come in place of question mark (?)in the given question?**

4 6 34 ? 504 1234- 194
- 160
- 186
- 156
- 172

Answer: Option B

Here the difference between each term is in the form of 13+1, 33+1, 53+1, 73+1 and so on

4 6 34 160 504 1234

+2 +28 +126 +344 +730

1^{3}+ 1 3^{3}+ 1 5^{3}+ 1 7^{3}+ 1 9^{3}+ 1

So ? = 160

Hence answer is option B**A and B are two numbers. 6 times square of B is 540 more than the square of A. if the respective ratio between A and B is 3:2. What is the value of B?**- 10
- 12
- 16
- 8
- 14

Answer: Option B.

We are given that

6B^{2}= A^{2}+ 540 and A : B = 3 : 2

Put the value of A from 2nd equation into the first equation, we get

6B^{2}= (1.5B)2 + 540

→ (6 – 2.25)B^{2}= 540 → 3.75B^{2}= 540 → B^{2}= 144 → B = 12

Hence answer is option B.